ABCD is a parallelogram. The circle through A, B and C intersect CD (produced if necessary) at E. Find value of
| AE | 
| AD | 
                Answer: 
            
        1

- ∠ABC = 180° - ∠AEC [ Opposite angels of cyclic quadrilateral are supplementary.]
 - Since ∠ABC = ∠ADE   [ Opposite angles of parallelogram are equal.]
∠ADE = 180° - ∠AEC - ∠ADE = ∠AED [ 180° - ∠AEC = ∠AED]
 - Since ADE is isosceles with angles ∠ADE = ∠AED, AD = AE, therefore  
= 1.AE AD  
 
        