ABCD is a parallelogram. The circle through A, B and C intersect CD (produced if necessary) at E. Find value of
AE |
AD |
Answer:
1
- ∠ABC = 180° - ∠AEC [ Opposite angels of cyclic quadrilateral are supplementary.]
- Since ∠ABC = ∠ADE [ Opposite angles of parallelogram are equal.]
∠ADE = 180° - ∠AEC - ∠ADE = ∠AED [ 180° - ∠AEC = ∠AED]
- Since ADE is isosceles with angles ∠ADE = ∠AED, AD = AE, therefore
= 1.AE AD