Find the length of the longest pole that can be put in a hall of dimensions ^@13 \space m^@ by ^@ 12 \space m ^@ by ^@ 5 \space m.^@


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Answer:

^@18.385 \space m^@

Step by Step Explanation:
  1. Here,
    ^@ \begin {align} l & = 13 \space m \\ b & = 12 \space m \\ h & = 5 \space m \end {align}^@
  2. ^@ \begin {align} \text {Length of the longest pole} & = \text {Length of the diagonal} \\ & = \sqrt {l^2 + b^2 + h^2 } \space units \\ & = \sqrt {(13)^2 + (12)^2 + (5)^2} \space m \\ & = \sqrt {169 + 144 + 25} \space m \\ & = \sqrt {338} \space m \\ & = 18.385 \space m \end {align}^@
  3. Therefore, the length of the longest pole that can be put in a hall of dimensions ^@13 \space m^@ by ^@ 12 \space m ^@ by ^@ 5 \space m^@ is ^@18.385 \space m^@.

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