If ^@ cot \space \theta + cosec \space \theta = \sqrt { 2 } \space cot \space \theta, ^@ show that ^@ cot \space \theta - cosec \space \theta = \sqrt { 2 } \space cosec \space \theta ^@


Answer:


Step by Step Explanation:
  1. We have @^cot \space \theta + cosec \space \theta = \sqrt { 2 } \space cot \space \theta@^ By squaring both the sides, we get ^@ \begin{aligned} &(cot \space \theta + cosec \space \theta)^2 = (\sqrt { 2 } \space cot \space \theta)^2 \\ \implies & cot^2 \space \theta + cosec^2 \space \theta + 2 \space cot \space \theta \space cosec \space \theta = 2 \space cot^2 \space \theta \\ \implies & cosec^2 \space \theta = 2 \space cot^2 \space \theta - cot^2 \space \theta - 2 \space cot \space \theta \space cosec \space \theta \\ \implies & cosec^2 \space \theta + cosec^2 \space \theta = cot^2 \space \theta - 2 \space cot \space \theta \space cosec \space \theta + cosec^2 \space \theta \space \space[\text{ Adding } cosec^2 \space \theta \text{ on both the sides. }] \\ \implies & 2 \space cosec^2 \space \theta = ( cot \space \theta - cosec \space \theta )^2 \\ \implies & cot \space \theta - cosec \space \theta = \sqrt{ 2 } \space cosec \space \theta \\ \end{aligned}^@
  2. Hence, ^@cot \space \theta - cosec \space \theta = \sqrt{ 2 } \space cosec \space \theta^@.

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