The sum of the squares of two consecutive natural numbers is 313. Find the numbers.
Answer:
12 and 13
- Let the numbers be x and x+1.
- x2 + (x+1)2 = 313
- 2x2 + 2x + 1 = 313
- 2x2 + 2x - 312 = 0
- x2 + x - 156 = 0
- x2 + 13x - 12x - 156 = 0
- x(x + 13) - 12(x + 13) = 0
- (x - 12) (x + 13) = 0
- x = 12 or -13. Since x cannot be negative, x = 12. Hence, numbers are 12 and 13.